std::chrono::operator==,<=>(std::chrono::year_month_day_last)
From cppreference.com
< cpp | chrono | year month day last
| Defined in header <chrono>
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| constexpr bool operator==( const std::chrono::year_month_day_last& x, const std::chrono::year_month_day_last& y ) noexcept; |
(1) | (since C++20) |
| constexpr std::strong_ordering operator<=>( const std::chrono::year_month_day_last& x, |
(2) | (since C++20) |
Compares the two year_month_day_last values x and y. This is a lexicographical comparison: the year() is compared first, then month().
The <, <=, >, >=, and != operators are synthesized from operator<=> and operator== respectively.
Return value
1) x.year() == y.year() && x.month() == y.month()
2) x.year() <=> y.year() != 0 ? x.year() <=> y.year() : x.month() <=> y.month()
Notes
If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.
Example
Run this code
#include <cassert> #include <chrono> #include <iostream> int main() { auto ymdl1{11/std::chrono::last/2020}; auto mdl{std::chrono::last/std::chrono::November}; auto ymdl2{mdl/2020}; assert(ymdl1 == ymdl2); ymdl1 -= std::chrono::months{2}; ymdl2 -= std::chrono::months{1}; assert(ymdl1 < ymdl2); }